The volume of co2 produced by the combustion of 40 ml of gaseous acetone in excess of oxygen
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2C2H2+5O2→4CO2+2H2O
By Gay-Lussac’s Law of combining volumes,
52×40=100 mL of O2 will be required.
By similar calculations, we get,
80 mL of CO2
and 40 mL of H2O (in the gaseous state)
Hope it helps!!
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