the volume of cylinder is 54 cm cube and its height is 16 cm what will be its curved surface area
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vol of cylinder=πr^2h
54 =22/7*r^2*16 54*7/22*16 =r^2
r^2=378/352
r^2=1.07
r=√1.07
r=1.4
curved surface area of cylinder=2πrh
=2*22/7*1.4*16
=44*0.2*16
= 44*3.2
=14.08
54 =22/7*r^2*16 54*7/22*16 =r^2
r^2=378/352
r^2=1.07
r=√1.07
r=1.4
curved surface area of cylinder=2πrh
=2*22/7*1.4*16
=44*0.2*16
= 44*3.2
=14.08
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