Question

the volume of cylindrical pipe 748cm3 its length is 0.14m and its internal radius is 0.09m . find the thick of pipe

Answer 1

vol=748cm3
h=0.14m×100=14cm
int rad=0.09m×100=9cm
therefore, pie(R2-r2)×0.14=748 (where R=ext radius and r=int radius)
R2-(9)2=748÷3.14×14
R=9.9cm
thockness= R-r=9.9-9=o.9cm

Answer 2

Given,

Volume of a cylindrical pipe= 748cm^3

length = 0.14m or, .14× 100 or, 14cm

Internal radius = 0.09 or, 0.09× 100 or, 9cm

Let's think the external radius is R

Now,

The volume of a cylindrical pipe = π (R^2 - r^2)× h

748= 22/7 (R^2 - 9^2)×14

or, 748 = 22/7 ( R^2 - 81)× 14

or, 748/14 = 22/7 ( R^2 - 81)

or,748/14× 7/22 = R^2 - 81

or, 17 + 81 = R^2

or,98 = R^2

or, R = 9.89

Now the thickness = R- r

= 9.89 -9

= 0.89 cm

Hope it helps