The volume of decimolar aqueous solution of hcl acid is required to prepare 2 dm cube of 5M hcl solution
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Volume of decamolar aqueos solution of HCl acid is required to prepare 2dm3 of 5M ... M1=10 v1=x m2=5 v2=2 M1 v1=m2v2 So answer is 1litre.
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Answer:
One liter
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