Question

The volume of decimolar solution of Hcl to required to prepare 2dm cube of 5M Hcl solution​

Answer 1

Answer:

you would use the M1V1 = M2V2 equation. we don’t have to convert mL to L because it’s gonna cancel out anyways.

M1 = 2 M

V1 = 500 mL

M2 = 0.5 M

V2 = ?

(2M)(500mL) = (0.5M)(V2) so V2 = 2000 mL

be careful, this is not the answer. this V2 = 2000 mL implies that this is going to be the TOTAL final volume.

we already have an initial 500 mL of HCL, sooooooooooo…. 2000 mL - 500 mL = 1500 mL

you would need to add 1500 mL of water in order to achieve a 0.5 M concentration.