Question

the volume of frustrum is __cm3 in which height 3cm and radii of both end circles are 5 and 3 cm

Answer 1

Volume of the Frustum
$= \frac{1}{3}\pi \: h( {r1}^{2} + {r2}^{2} + r1r2 ) \\ = \frac{1}{3}\pi \: 3( {5}^{2} + {3}^{2} + 5 \times 3) \\ = \frac{1}{3}\pi \: 3(25 + 9 + 15) \\ = \frac{1}{3} \times \frac{22}{7} \times 3 \times 49 \\ = 164 {cm}^{2}.$





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Answer 2

Hi Mate !!

Solution :

Heigh of frustum ( H ) = 3 cm.

Radius of top of frustum ( R ) = 5 cm.

Radius of bottom of frustum ( r ) = 3 cm.

Therefore,

Volume of frustum = πH / 3 × ( R² + r² + Rr )

Volume of frustum = 22 × 3 /7 × 3 ( 5² + 3² + 5*3 ).

=> 66 / 21 × ( 25 + 9 + 15 ) cm³.

=> 22 / 7 × 49 cm³.

=> 22 × 7 cm³.

=> 154 cm³.

Hence,

The volume of frustum is 154 cm³ in which heigh 3 cm and radii of both end circle's are 5 and 3 cm.


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By Rishi403

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