Question

The volume of gas at ntp produced by 100 g of cac2 with water

Answer 1

CaC2+2H2o ---Ca(OH)2+C2H2. Means 1mole of cac2 gives 1mole of acetylene or 22.4 lit of gasNow 64g of CaC2 gives 22.4 lit. So 100g of CaC2 gives 22.4* 100/64 = 35 lit of gas ( here * used for multiplication.

Answer is 35 litre.

Answer 2

Answer:

35 L is the volume.

Step-by-step explanation:

When calcium carbide reacts with water it produces calcium hydroxide and releases ethyne gas.

CaC2(s) + H2O(l) ------> Ca(OH)2 (aq) + C2H2(g)

Number of moles = Mass of given substance/Mass of one mole = 100/64

Here, 1 mole = 22.4 L.

Volume = 100/64 × 22.4 = 35 L.

.°. Volume = 35 L