Question

The volume of gas at NTP produced by 100 gm of CaC2 with water-

Answer 1

CaC2+2H2o ---Ca(OH)2+C2H2. Means 1mole of cac2 gives 1mole of acetylene or 22.4 lit of gasNow 64g of CaC2 gives 22.4 lit. So 100g of CaC2 gives 22.4* 100/64 = 35 lit of gas ( here * used for multiplication
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Answer 2

Answer:

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Explanation:

When calcium carbide reacts with water it produces calcium hydroxide and releases ethyne gas.

CaC2(s) + H2O(l) ------> Ca(OH)2 (aq) + C2H2(g)

Number of moles = Mass of given substance/Mass of one mole = 100/64

Here, 1 mole = 22.4 L.

Volume = 100/64 × 22.4 = 35 L.

.°. Volume = 35 L