Question

The volume of gas in a balloon is 1.90 L at 21.0°C. The balloon is heated, causing it to expand to a volume of 5.70 L. What is the new temperature of the gas inside the balloon?

Answer 1

Answer:

The temperature of the gas is 609 °C.

Explanation:

Temperature of the gas when the volume of the gas 1.90 L = 21°C = 294 K

Temperature  of the gas when the volume of the gas was 5.70 L=  T

Applying Charles's law:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\frac{1.90 L}{294 K}=\frac{5.70 L}{T}$

T = 882 K =  609 °C

The temperature of the gas is 609 °C.

Answer 2

Explanation:

Answer:

1st equation answer is X= -1 and 2nd equation answer is X= 4

Answer 3

Explanation:

Answer:

1st equation answer is X= -1 and 2nd equation answer is X= 4