Question

The volume of given mass of dry gas at 20℃ is 100cm^3. At what temperature the volume of the gas will be 125 cm^3. (Keeping the pressure constant)​

Answer 1

Answer:

Explanation:

V1/T1 = V2/ T2  ( Charles Law)

V1 = 100cm³

V2 = 125cm³

T1 = 20°C

T2 = ?

100 / 20 =  125 / T2

5 = 125/ T2

T2 = 125/ 5

T2 = 25° C

Answer 2

$\boxed{\red{AnswEr:-}}$

➟ 93.25 ℃

★ GivEn :-

• Initial Volume = 100 cm^3
• Final Volume = 125 cm^3
• Initial temperature = 20 ℃

★ To FinD :-

• Final temperature.

★ SolutiOn :-

➟ According to Charles law,

The volume of a fixed amount of dry gas is proportional to the absolute or Kelvin temperature when the pressure is constant.

➟ $\sf {Equation \: of \: Charles \: Law \: : \: V \propto T}$

➟ Hence, it can be written as,

$\large{\boxed{\sf{\dfrac{V_1}{V_2} = \dfrac{T_1}{T_2}}}}$

• $\sf {V_1} = { Initial \: Volume }$

• $\sf {V_2} = { Final \: Volume }$

• $\sf {T_1} = { Initial \: absolute \: temperature }$

• $\sf {T_2} ={ Final \: absolute \: temperature }$

➟ The absolute temperature of 20℃ is

= (273 + 20) K or 293 K

➟ As per given in the question, putting the values we get,

$\large{\sf{\dfrac{100}{125} = \dfrac{293}{T_2}}}$

Or, $\large{\sf {T_2} = \dfrac{125 \times 293}{100}}$

Or, $\large{\sf {T_2} = {366.25}}$

➬ $\large{\sf { The \: initial \: temperature \: is \: 366.25 }}$

$\large{\sf { or \: {( \: 366.25 \: - \: 273 \: )}^{\circ}C \: = \: {93.25}^{\circ}C }}$