Question

the volume of given mass of gas will be double at atmospheric pressure.if the temperature of gas is changed from 150°C to?

Answer 1

At constant pressure
V ∝ T

V₂/V₁ = T₂/T₁
2V₁/V₁ = T₂ / (150 + 273)
T₂ = 846 K
T₂ = 573°C

∴ Volume doubles of temperature of gas is changed to 846 K (= 573°C)

Answer 2

Concept:

In a closed system, the volume of a gas with constant pressure is directly proportional to the temperature in Kelvin.

Given:

Initial temperature = 150°C

Constant atmospheric pressure

Find:

The final temperature

Solution:

According to Charle's law

At constant pressure

Volume is directly proportional to Temperature

V ∝ T

V = KT where K is a constant

V/T = K

So initially V/T will be equal to final V/T

Initially V is v and T is 150°C or 423.5K

Final V is 2v and T will be Tf

Initial (V/T) = final (V/T)

v/423.5 = 2v/Tf

Tf = 2 * 423.5 K

Tf = 847 K or 573.85°C

Hence The temperature of the gas will change from 150°C  to 573.85°C.

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