Chemistry, asked by mostafaemam19801, 19 days ago

The volume of hydrogen which is required to produce 11.2 L of water vapour (at STP)=​

Answers

Answered by jaldiiik
0

Answer:

I don't know answer srry dear

Answered by NirmalPandya
0

For the production of water, the following reaction will take place between hydrogen gas a and oxygen gas

2H₂ +  O₂ → 2H₂O

According to this equation, 2 moles of H₂ will react with 1 mole of O₂ to produce 2 moles of H₂O.

We know that 1 mole contains 22.4L of an ideal gas at STP

Let us consider these gases as ideal

2H₂           +         O₂           → 2H₂O

2x22.4L                22.4L         2x22.4L

On diving the equation by 2

H₂           +         1/2O₂           → H₂O

22.4L                 11.2L                 22.4L

On further dividing the equation by 2

1/2H₂           +         1/4O₂           →1/2 H₂O

11.2L                        5.6L               11.2L

Therefore, we can see that 11.2L of hydrogen gas will produce 11.2L of water.

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