Math, asked by indar3042, 1 year ago

The volume of metallic cylindrical pipe is 748 centimetre cube its length is 14 cm and its external radius in 9 cm find its thickness

Answers

Answered by TheGSD
0
The thickness is 0.5 cm
don't ask for explanation
Answered by MPCgenius
3

<b>Answer</b> :

8 cm

<b>Step - By - Step Explanation</b> :

<b>Given</b>: Volume of cylindrical pipe = 748 cm³ and it's length is 14 cm and external radius is 9 cm .

<b>We know that</b> : πR²h - πr²h , Where R represents another radius of pipe and r represent original radius of pipe,

<b>Now, We have</b>

πR²h - πr²h = 748 cm³

πh (R² - r² ) = 748 cm³

πh [ ( 9)² - (r²) ] = 748 cm³

π.14 [ 81 - r² ] = 748 cm³

14 π [ 81 - r² ] = 748 cm³

π [ 81 - r² ] = 748 ÷ 14

[ 81 - r² ] = 748 ÷ 14 ÷ π

[ 81 - r² ] = 748 ÷ 22/7 × 14

<b>[ 81 - r² ] = 748 ÷ 44</b>

[ 81 - r² ] = 17

- r² = 17 - 81

- r² = - 64

r² = 64 cm ²

r = √64 cm

•°• \sf{\boxed{\boxed{\bf{r\:= \:8 \:cm}}}}

<b>Hence , Required thickness ( radius ) of internal cylindrical pipe is 8 cm</b>

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