the volume of O2 at STP required for the complete combustion of 4g CH4
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CH4 + 2.5O2 ———> CO2 + 2H2O
Molar mass of CH4 = 16 g
From balanced equation, at STP
16 g of CH4 requires (2.5 * 22.4)L of O2
Then 4 g of CH4 will require = (4 * 2.5 * 22.4) / 16 = 14 L of O2
Volume of O2 required is 14 L
Hope this will help!
Molar mass of CH4 = 16 g
From balanced equation, at STP
16 g of CH4 requires (2.5 * 22.4)L of O2
Then 4 g of CH4 will require = (4 * 2.5 * 22.4) / 16 = 14 L of O2
Volume of O2 required is 14 L
Hope this will help!
Tanisha1431:
2.5 O2 means??
To balance the reaction,we have to multiply 2.5 to O2
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