The volume of O2 at STP required for the complete combustion of4g CH4 is
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If 1 mole of CH4 requires 2 moles of O2 for complete combustion. Therefore, 1/4 mole of CH4 will requires = 1/4 ×2 moles of O2 = 0.5 mol of O2 for complete combustion. So 11.2 L of O2 is required for complete combustion of 4 g CH4.
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