Question

The volume of O2 at STP required for the complete combustion of 4 g CH4 is
(1) 5.6 litre
(2) 2.88 litre
(3) 22.4 litre
(4) 11.2 litre
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Answer 1

HeRe Is Your Ans ⤵

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The balanced chemical equation for combustion of methane is given as:

CH4 + 2O2 → CO2 + 2H2O

So 1 mole of CH4 requires 2 moles of O2 for complete combustion.

Molar mass of methane = 16 g.

Number of moles of methane in 4 g sample = 4 g/16 g = 1/4 mole

If 1 mole of CH4 requires 2 moles of O2 for complete combustion

Therefore,

1/4 mole of CH4 will requires = 1/4 ×2 moles of O2 = 0.5 mol of O2 for complete combustion.l

1 mole of all the gases occupy 22.4 L at STP

Therefore 0.5 mole will occpy 22.4 L × 0.5 mol = 11.2 L

So , 11.2 L of O2 is required for complete combustion of 4 g CH4

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