Chemistry, asked by anima634622, 11 months ago

The volume of O2 liberated at STP from 0.68 grams of H2O2 is?

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Answered by shrawan85356

4

Answer:

2H2O2→2H2O+O2 2×34g22400ml ∵2×34g=68g of H2O2 liberates 22400mlO2 at STP ∴0.68gof H2O2 ... ·

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