Chemistry, asked by punypunj16, 10 months ago

The volume of O2 obtained at STP, when 12.25 g of KClO3 is decomposed, is (Molar mass of KClO3 = 122.5 g/mol) 2.24 L 1.12 L 3.36 L 4.48 L

Answers

Answered by bhavanamulthalli

2

Answer:2.24

Explanation:As 12.25g of KClO3 is 0.1 mole he vol of O2 liberated is (22.4)*0.1=2.24L

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