the volume of open cylindrical can is 6358 cm3 and its height is 28 cm. find its radius and curved surface area
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Answered by
9
Volume of cylinder = 22/7 * r * r * h
h = 28
22/7 * r *r * 28 = 6358
88*r*r = 6358
r*r = 6358/88
r*r = 72.25
r = square root of 72.25
r = 8.5
Ans: 8.5 cm
and curved surface area= 2πrh
=2×π×8.5×28
=1495.39 cm^2
h = 28
22/7 * r *r * 28 = 6358
88*r*r = 6358
r*r = 6358/88
r*r = 72.25
r = square root of 72.25
r = 8.5
Ans: 8.5 cm
and curved surface area= 2πrh
=2×π×8.5×28
=1495.39 cm^2
Answered by
9
given,
volume of cylinder =π r² h = 6358
22/7 × r² × 28 = 6358
88 r² = 6358
r² = 6358 / 88
r² = 72.25
r =√72.25
r = 8.5 cm
curved surface area of cylinder = 2πrh
= 2 × 22/7 × 8.5 × 28
= 1496 cm²
volume of cylinder =π r² h = 6358
22/7 × r² × 28 = 6358
88 r² = 6358
r² = 6358 / 88
r² = 72.25
r =√72.25
r = 8.5 cm
curved surface area of cylinder = 2πrh
= 2 × 22/7 × 8.5 × 28
= 1496 cm²
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