the volume of oxidation number of cl in cl2, Naocl and clo-3
Answers
Answered by
1
Answer:
Oxidation no. of chlorine =+7
Suppose oxidation number of chlorine is x then , 1+x+4×(−2)=0
∴x−7=0
x=+7
Answered by
1
Oxidation no. of Chlorine =+7
Suppose oxidation number of chlorine is x then, 1 + x + 4 × (-2) = 0
Therefore, x - 7 = 0
x = +7
Similar questions