The volume of oxygen at ntp evolved when 1.70 g of sodium nitrate is heated to a constant mass is:
Answers
Answered by
0
Answer:
5,6 lt
Explanation:
2NaNO3 ---> 2NaNO2 + O2
2 moles of sodium nitrate ---> 1 mole of oxygen
1.7/85= 0.5 moles of sodium nitrate gives 0.25 moles of oxygen
therefore volume = 0.25 x 22.4 = 5.6 lt
Similar questions