the volume of Oxygen at STP required to burn 2.4 g of carbon completely is
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Explanation:
The chemical equation for the process is:
C+O2 →CO2
For the above reaction, 1 mole of O2 will burn 1 mole of C completely.
In 2.4 g C, number of moles = 2.4/12 =0.2 moles of oxygen is required.
Volume occupied by 1 mole of an ideal gas at STP (T=0K and P=1atm) is 22.4L.
Therefore, 0.2 mol OO =0.2×22.4 L
=4.48L.
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