Question

The volume of oxygen at STP required to completely burn 2.2g of of propane(C3H8) is ​

Answer 1

Answer:

5.6 litre

Propane

C

3

H

8

(g)

+

(5O

2

)

(3+

4

8

)O

2

→3CO

2

+4H

2

O

Mass of propane =2.2 g

Moles of propane =

44 g

2.2 g

=

20

1

Volume at NTP =

20

1

×22.4 lit=1.12 lit

∴ 1 volume of C

3

H

8

≡5 volume of O

2

Volume of O

2

=5× volume of C

3

H

8

Volume of O

2

=5×1.12 lit=5.6 lit