Question

The volume of oxygen at STP required to completely burn 30 ml of acetylene at STP is:
(1)100ml
(2)75ml
(3)50ml
(4)25ml????

Answer 1

Answer:

Ans 2 - 75ml

Explanation:

Answer 2

The volume of oxygen at STP required to completely burn 30 ml of acetylene at STP is 75 ml

Explanation:

According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = 1 atm

V= Volume of the gas = 30 ml = 0.03 L

T= Temperature of the gas in kelvin = 273 K

R= Gas constant = 0.0821 Latm/Kmol

n=  moles of gas= ?

$n=\frac{PV}{RT}=\frac{1\times 0.03}{0.0821\times 273}=1.34\times 10^{-3}$

The balanced chemical reaction is :

$2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O$

Thus for 2 moles of acetylene we require 5 moles of oxygen

For $1.34\times 10^{-3}$ moles of acetylene we require =$\frac{5}{2}\times 1.34\times 10^{-3}=3.35\times 10^{-3}$ moles of oxygen

For volume of oxygen at STP

$V=\frac{nRT}{P}=\frac{3.35\times 10^{-3}\times 0.0821\times 273}{1}=0.075L=75ml$

Thus volume of oxygen at STP required to completely burn 30 ml of acetylene at STP is 75 ml

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