Question

The volume of oxygen gas liberated at ntp by passing 9650 c through acidified water

Answer 1

Answer:

yes the sentence is absolutely correct .

Explanation:

Answer 2

The volume of oxygen gas liberated at NTP by passing 9650 c through acidified water is equal to 560 ml.

• 9650 C of charge is equivalent to 0.1 F(i.e,0.1 moles of electrons).
• One mole of oxygen gas is produced by the release of 4 moles of electrons, so 0.1 moles of electron released will produce 0.025 moles of oxygen gas.
• One mole of a gas occupies 22.4 L of volume at NTP , so 0.025 moles of oxygen will occupy 0.56 L(0.025×22.4).