Question

The volume of oxygen required for complete combustion of a mixture of 5 cc of
methane (CH4) and 5 cc of ethylene (C2H4) is

1.5 cc
2. 10 cc
3.25 cc
4. 50 cc​

Answer 1

1- ml of ethene (ethylene) requires 3- ml of oxygen. Therefore for the complete combustion of 5- ml of CH4 and 5- ml of C2H4 the minimum volume of oxygen required for complete combustion is (5 x 2) +(5 x 3) = 10 + 15= 25- ml.

Answer 2

A correct answer is option (c). $25cc$

Given:

A mixture of 5 cc of methane $CH_{4}$ and 5 cc of ethylene $C_{2} H_{4}$

To Find:

The volume of oxygen required for full combustion of a mixture of 5 cc of methane $CH_{4}$ and 5 cc of ethylene $C_{2} H_{4}$

Solution:

As we know,

a Balanced Equation is $CH_{4} + 2O_{2}$→$CO_{2} + 2H_{2}O$

$1cm^{3}$  $CH_{4}$ needs $2cm^{3}$ $O_{2}$

Thus, $5cm^{3}$ $CH_{4}$ needs $10cm ^{3}$ $O_{2}$

A balanced equation of complete combustion is

$C_{2}H_{4} + 3O_{2}$→$2CO_{2} + 2H_{2}O$

Similarly,

$5cm^{3}$ $C_{2}H_{4}$ needs $15cm^{3}$$O_{2}$

The total volume of oxygen needed for full combustion.

$= 10cm^{3} + 15cm^{3}$

$= 25cm^{3}$

Therefore, The volume of oxygen required for complete combustion is $25cm^{3}$.

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