Question

the volume of oxygen required for complete oxidation of 2.0 liter of methane at NTP

Answer 1

here is your answer..

assume everything is at NTP. if starting with one mole of methane, Need 2 .

So you need 5 volumes total of oxygen. 


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Answer 2

For this problem, we can use Gay-Lussac's Law of Combining Volumes:

If pressure and temperature are constant, the ratio between the volumes of the reactant gases and the products can be expressed in simple whole numbers.

The balanced equation for the combustion is

l
CH
4
+
2O
2
→
CO
2
+
2H
2
O

1 dm
3
l
l
2 dm
3


According to Gay-Lussac,
1 dm
3
l
of CH
4
requires
2 dm
3
l
of O
2
.

∴
Volume of O
2
=
0.25
dm
3
l
CH
4
×
2 dm
3
l
O
2
1
dm
3
l
CH
4
=
0.50 dm
3
l
O
2