Question

The volume of oxygen used when x gms of Zn is converted to ZnO is
(a) 653 5.6 litres (6) * *5.6 litres
(c) ** *5.6 litre​

Answer 1

Answer:

5.6 litres 5.6 5.6 5.6 5.6 5.6 5.6 5.6 .5 .6

Answer 2

Answer:The volume of oxygen used when x grams of Zn is converted to ZnO is (x / 130.76) × 22.4 liters.

Explanation:

• When zinc (Zn) reacts with oxygen (O2) then zinc oxide (ZnO) is formed.

          2 Zn + O2 → 2 ZnO

• Now according to the above chemical equation, we see that 1 mole of O2 reacts with two moles of Zn to produce two moles of ZnO. The molar extent of any fuel at standard temperature and pressure is 22.4 liter.

• Molar mass of Zinc = 65.38 g/mol

• Number of moles of Zinc= x / 65.38

• By using the stoichiometry of the balanced chemical equation, moles of O2 required:

2 moles of Zn react with 1 mole of O2

Number of moles of O2 = (x / 65.38) / two = x / 130.76

Now the extent of O2 at STP is :

Volume of O2 = (x / 130.76) × 22.4 liters

• Therefore, the volume of oxygen used when x grams of zinc is converted to ZnO is (x / 130.76) × 22.4 liters

To learn more about molar mass from the given link-

https://brainly.in/question/48308900

To learn more about stoichiometry from the given link-

https://brainly.in/question/1106150

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