Question

The volume of oxygen used when x gms of Zn is
converted to ZnO is​

Answer 1

Answer:

The volume of oxygen used when x gms of Zn is converted to ZnO is (a) 653 5.6 litres (6) * *5.6 litres.

Answer 2

Answer:

The volume of oxygen used when x grams of Zn is converted to ZnO is (x / 130.76) × 22.4 liters.

Explanation:

From the above question,

The response between zinc (Zn) and oxygen (O2) to structure zinc oxide (ZnO) is as follows:

           2 Zn + O2 → two ZnO

According to the balanced chemical equation, 1 mole of O2 reacts with two moles of Zn to produce two moles of ZnO. The molar extent of any fuel at widespread temperature and stress (STP) is 22.4 liters.

Therefore, the extent of oxygen used when x grams of Zn is transformed to ZnO can be calculated as follows:

Calculate the wide variety of moles of Zn the use of its molar mass:

Molar mass of Zn = 65.38 g/mol

Number of moles of Zn = x / 65.38

Using the stoichiometry of the balanced chemical equation, calculate the variety of moles of O2 required:

2 moles of Zn react with 1 mole of O2

Number of moles of O2 = (x / 65.38) / two = x / 130.76

Calculate the extent of O2 at STP the usage of the molar volume:

Volume of O2 = (x / 130.76) × 22.4 liters

Therefore, the quantity of oxygen used when x grams of Zn is transformed to ZnO is (x / 130.76) × 22.4 liters.

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