Question

The volume of ratio of 6n and 2n hcl required to prepare 100ml of 5n hcl is

Answer 1

Answer:

Explanation:

let x =liters of 6n Hcl

let y =liters of 2n Hcl

x + y =0.100L

6x +2y/0.100 =5

x =0.100-y

6(0.100-y)+2y=0.5

x=0.100-y

0.600-6y+2y=0.5

x=0.100-y

4y=0.1

x=0.100-y

y=0.025L of 2n Hcl =>25ml

x=0.100-0.025=0.075L of hcl

6n=75mL