Question

the volume of region bounded by the surface Y=X 2 and x=y2 and plane z=0 and z=3 is​

Answer 1

Answer:

How do you find the volume of the region bounded by surface y^2=4ax and x^2 = 4ay and the plane z=0 and z=3?

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The intersection points are (0,0) and (4a,4a)

The volume is obtained by area in the z=0 plane multiplied by height 3.

The area is symmetrical about y=x line.

Area of one part=area of triangle (0,)(4a,0)and (4a,4a)minus the area under parabola which is one third of enclosing rectangle (square in this case)

A=2(12×4a×4a−13×4a×4a)

=2(8a2−23×16a2)

=16a23

V=A×3=16a

HOPE IT'S HELP YOU

Answer 2

Step-by-step explanation:

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