the volume of right circular cone of height 9cm is 48picm3 find its diameter and height
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0
volume of cone=1/3 pi r square h
48 pi = 1/3 pi r square* 9
48=1/3*9*r square
48 = 3*r square
48 /3=r square
16 = r square
r = 4
diameter = 8
48 pi = 1/3 pi r square* 9
48=1/3*9*r square
48 = 3*r square
48 /3=r square
16 = r square
r = 4
diameter = 8
Answered by
42
Let the radius of the base of the right circular cone be r cm
h = 9cm
Volume = 48πcm³
πr²h = 48π
r²h = 48
× r²h × 9 = 48
r² =
r² = 16
r = √16
4cm
2r = 2(4) = 8cm
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