Question

The volume of right circular cylinder of height 24 cm is 924 cm. Find the area of the curved surface of the cylinder
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Answer 1

Answer:

$\huge{\boxed{\rm{\red{Answer=528 cm²}}}}$

Step-by-step explanation:

Given:-

The volume of right circular cylinder of height 24 cm is 924 cm.

To find:-

Find the area of the curved surface of the cylinder.

Solution:-

Height of the right circular cylinder (h)=24 cm

Volume of the cylinder(V)=924 cm³

Used formula:-

If the radius and height of the right circular cylinder are "r" units and "h" units then The volume of the cylinder is πr²h cubic units.

V=πr²h=924

=>(22/7)×r²×24=924

=>r²=(924×7)/(22×24)

=>r²=(6×7×22×7)/(22×6×4)

Cancelling 22×6 then

=>r²=(7×7)/4

=>r²=7²/2²

=>r²=(7/2)²

=>r=7/2

radius is 7/2 cm

Now

Curved surface area of the cylinder is

2πrh sq.units

=>2×(22/7)×(7/2)×24 sq.cm

=>(2×22×7×24)/(7×2)

Cancelling 2×7 then

=>22×24

=>528sq.cm

Curved surface area=528 sq.cm

Answer:-

Curved Surface Area of the given cylinder is 528 sq.cm

Answer 2

Given :

• Volume of Cylinder is 924 cm³ .
• Height of Cylinder is 24 cm .

To Find :

• Curved Surface Area of Cylinder .

Solution :

Firstly we will find Radius :

$\longmapsto\tt{Height=24\:cm}$

Using Formula :

$\longmapsto\tt\boxed{Volume\:of\:Cylinder=\pi{{r}^{2}h}}$

Putting Values :

$\longmapsto\tt{924=\dfrac{22}{7}\times{{r}^{2}}\times{24}}$

$\longmapsto\tt{924\times{7}=22\times{{r}^{2}}\times{24}}$

$\longmapsto\tt{6468=528{r}^{2}}$

$\longmapsto\tt{\cancel\dfrac{6468}{528}={r}^{2}}$

$\longmapsto\tt{\sqrt{12.25}=r}$

$\longmapsto\tt\bf{3.5\:cm=r}$

So , The Radius of Cylinder is 3.5 cm ...

Now ,

$\longmapsto\tt{Radius=3.5\:cm}$

$\longmapsto\tt{Height=24\:cm}$

Using Formula :

$\longmapsto\tt\boxed{C.S.A\:of\:Cylinder=2\pi{rh}}$

Putting Values :

$\longmapsto\tt{2\times\dfrac{22}{7}\times{35}{10}\times{24}}$

$\longmapsto\tt{\cancel\dfrac{36960}{70}}$

$\longmapsto\tt\bf{528\:{cm}^{2}}$

So , The Curved Surface Area of Cylinder is 528 cm² ...