Question

The volume of solution of beaker is 200 mL, but it was read as 280 mL. Find the per cent error

Answer 1

Answer:

actual volume of solution - 200mL

volum of solution with errored read-280 mL

Error=280-200=80

200-100%

80-x

x=80*100/200=40%

•°• The percent error is 40%.

Hope it helps :)

Answer 2

$Solution \: of \: beaker \: is \: 200 \: ml$

$Error \: Showing = 280 \: ml$

$Error \: Shown = 280 - 200 \\ = 80$

$Error \: Percentage = 80 \times \frac{100}{200}$

$Error \: Percentage = 40 \: \%$