Question

the volume of space inside the right circular conical tent is 22m^3 and its vertical height is 3m. Find the curved surface area of conical tent.

Answer 1

Let r be the radius
height, h = 3 m
$volume \: = \frac{1}{3} \pi {r}^{2} h \\ \frac{1}{3} \times \frac{22}{7} \times {r}^{2} \times 3 = 22 \\ r = \sqrt{7} \: m \\ \\ slant \: \: height \: \: l = \sqrt{ {r}^{2} + {h}^{2} } \\ = \sqrt{ {( \sqrt{7} )}^{2} + {3}^{2} } = 4 \: m \\ curved \: \: surface \: \: area = \pi \times r \times l \\ = \frac{22}{7} \times \sqrt{7} \times 4 = 33.26 \: {m}^{2}$

Answer 2

ANSWER ANS STEP BY STEP EXPLATION IS EMPTY BECAUSE NO ANSWER