Question

the volume of sphere is 4851 cm sq how much should it radius be reduced so that it's volume becomes 4312/3 cm sq

Answer 1

Given :- Volume of the sphere = 4851 cm³
⇒ 4/3πr³ = 4851
⇒r³ = 4851*3*7/4*22
⇒ r³ = 441*21/8
⇒r = ∛ 21*21*21 / 2*2*2
⇒ r = 21/2
⇒ r = 10.5 cm.

According question :-
Volume reduced in the sphere = 4312/3 cm³ .
⇒ 4/3 π r³ = 4312/3
⇒ r³ = 4312*3*7 / 3*4*22
⇒ r³ = 196*7/4 
⇒r³ = 49*7
⇒ r = ∛ 7*7*7
⇒ r = 7 cm.

Radius reduction is 10.5 cm - 7 cm.
⇒ 3.5 cm
∴ The radius should be reduced 3.5 cm

Thank you.....!!!!
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Yours, Jahnavi.

Answer 2

yes of volume of Sphere 4851 will be 10.5 CM after simplification
radius of sphere of volume 4 3 1 2 by 3 will be 7 after simplification
show the difference between 10.5 and 7 is 3.5 show the radius should be reduced to 3.5 if its volume is to be 431 2 by 3 cm cube