Question

The volume of sphere is 4851 cm³. How much should its radius be reduce so that its volume become 4312/3 cm³ ?

Answer 1

volume of sphere is 4/3πr³
so,let be common radius be r for both the statement
let reducing value be p.
from the 1st statement 4/3πr³=4851
solving the form will give r³=1158.0909
∴r=10.5
from the 2nd statement 4/3π(r-p)³=4312/3
solving the above form (r-p)³=343
∴(r-p)=7
substituting r=10.5 in above then (10.5-p)=7
∴-p=-3.5
p=3.5 i.e., reduced radius is 3.5 and after reduced radius is 7. 

Answer 2

Here is the solution: Volume of the sphere = 4851 cm3 For volume of the sphere = 4312/2 cm3  ï»¿

Therfore change in radius = 10.49 - 6.99 = 3.59 cm