Question

The volume of sphere is 88/21 find its surface area​

Answer 1

SOLUTION:-

Given:

The volume of sphere is 88/21m³.

We know that, Volume of spheres is;

$= > \frac{4}{3} \pi {r}^{3}$

Therefore,

$= > \frac{4}{3} \pi {r}^{3} = \frac{88}{21} \\ \\ = > \frac{4}{3} \times \frac{22}{7} \times {r}^{3} = \frac{88}{21} \\ \\ = > \frac{88}{21} \times {r}^{3} = \frac{88}{21} \\ \\ = > {r}^{3} = \frac{ \frac{ \frac{88}{21} }{88} }{21} \\ \\ = > {r}^{3} = \frac{88}{21} \times \frac{21}{88} \\ \\ = > {r}^{ 3} = 1 \\ \\ = > r = 1m$

Now,

We know that, surface area of sphere is;

$= > 4\pi {r}^{2}$

Therefore,

$= > 4 \times \frac{22}{7} \times (1) {}^{2} \\ \\ = > \frac{88}{7} \times 1 \\ \\ = > 12.57m {}^{2}$

Thus,

The surface area of the sphere is 12.57m².

Hope it helps ☺️

Answer 2

The surface area of the  sphere is calculated to be  $\frac{88}{7} m^2$

Step-by-step explanation:

The volume of a sphere = $\frac{4}{3}\pi r^3$

and the surface area of sphere =  $4\pi r^2$

It is given in the question that volume is $\frac{88}{21}m^3$

Using volume, the radius of the sphere can be calculated as follows:

$\frac{88}{21}m^3$ =  $\frac{4}{3}\pi r^3$

$\frac{88}{21}m^3$ =  $\frac{4}{3}\pi r^3$

Rearranging we obtain,

$r^3 = \frac{88\times3}{21\times4\times\pi}$

or,  $r^3 = \frac{22}{7\pi}$ = 1

Thus, the radius of the sphere is 1 m.

Now, finding the surface area = $4\pi r^2 = 4\times \frac{22}{7} \times 1^2$ = $\frac{88}{7} m^2$