The volume of the bcc unit cell when the atomic radius is 0.662 nm
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We can conclude that the volume of the bcc unit cell when the atomic radius is 0.662 nm is 1.52 nm.
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Explanation:
It is known that relation between atomic radius and volume for a bcc unit cell is as follows.
a = \frac{4R}{\sqrt{3}}
3
4R
where, a = volume
R = radius
It is given that atomic radius is 0.662 nm or 0.662 \times 10^{-9}0.662×10
−9
m. Putting the given values into the above formula as follows.
a = \frac{4R}{\sqrt{3}}
3
4R
= \frac{4 \times (0.662 \times 10^{-9}}{\sqrt{3}}
3
4×(0.662×10
−9
= 1.52 \times 10^{-9}1.52×10
−9
m
or, = 1.52 nm
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