the volume of the circular iron rod of length 1m is 3850cm 3 find its radius
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length = 1m = 100 cm
Volume = πr^2(l)
3850 = 22/7 x r^2 x 100
385 = 220/7 x r^2
385 x 7/220 = r^2
12.25 = r^2
r = √12.25 = 3.5 cm
Radius of the rod is 3.5 cm
Volume = πr^2(l)
3850 = 22/7 x r^2 x 100
385 = 220/7 x r^2
385 x 7/220 = r^2
12.25 = r^2
r = √12.25 = 3.5 cm
Radius of the rod is 3.5 cm
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