Question

the volume of the rectangular tank with base
${76m}^{2} \: and \: 2m$
​

Answer 1

Answer:

-_-_-_-_-_-_--_-_-_-_-_-_-_-_-_--_-_-_-_-_-_-_-_-_-_-_--_-_-_-_-_-_-_-_-_-_--_-_-_

Answer 2

Answer:

Given that,

density of water (ρ)=103 Kg/m3

water fixed up till height (h)=2 m

Area of base (A)=100 m2.

assuming atmospheric pressure (P0)=1 atm≃105 Pa

so, pressure at bottom of tank,

P=P0+ρgh.

=105+103×10×2[g=10 m/s2]

P=(1.2×105) Pa

Thus, thrust on bottom surface,

F=P.A=(1.2×105)×102⇒F=1.2×107 N

Step-by-step explanation: