Question

The volume of two spheres are in ratio 64:343. Find the ratio of their surface area?

Answer 1

Let the radius of the two spheres be r and R respectively.

Given that ratio of volumes = 64:343.

4piR^3/4pir^3 = 64/343

(R/r)^3 = 64/343

R/r = 4/7.


Ratio of the surface area = 4piR^2/4pir^2

                                           = (R/r)^2

                                           = (4/7)^2

                                           = 16/49

                                           = 16:49.



Hope this helps!

Answer 2

bro u can take r1^2:r2^2 or r^2 1:r^2 2


volume of sphere1 : volume of sphere 2= 64:343
4/3πr^3 1 : 4/3πr^3 2=64:343
r^3 1: r^3 2= 64:343
r1:r2=cube√64:cube√343
r1:r2=4:7
ratio of surface area of sphere=4πr^2 1:4πr^2 2
=r^2 1:r^2 2
= 4^2:7^2
=16:49

hope it helps u.