The volume of water that must be added to a.mixture of 250 ml of 0.6 m HCl and 750ml of 0.2 m HCl to obtain 0.25 solution of HCl?
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No. of moles of 0.6M HCl = 0.15
No. of moles of 0.2M HCl = 0.15
let V be the volume(in ml) of the 0.25M solution. No of moles present = 0.15+0.15 = 0.3
0.3×1000/V(ml) = 0.25M
V = 1.2L
No. of moles of 0.2M HCl = 0.15
let V be the volume(in ml) of the 0.25M solution. No of moles present = 0.15+0.15 = 0.3
0.3×1000/V(ml) = 0.25M
V = 1.2L
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