Question

The volume of water that must be added to a mixture of 250 ml of 6M HCL and 650no of3M HCL to obtain 3M solution.​

Answer 1

ans:(4)

When two solutions are mixed together to form a solution, we apply the formula:

M1V1+M2V2=M×VM1V1+M2V2=M×V, where M1,M2,V1,V2M1,M2,V1,V2 are the molarity of the solutions being mixed, and M and V are the molarity of the final solution.

250×6+650×3=3×V250×6+650×3=3×V

⟹V=1150 ml⟹V=1150 ml

The total volume of the solution is 1150 ml. The volume present initially is (250 + 650) = 900 ml solution. We need to add 250 ml of water to obtain 3M solution.