Question

The volume of water to be added to 100cm3 of 0.5N H2SO4 to get decinormal concentration

Answer 1

Given N as the normality, a decinormal concentration would be :

N/10

In this case :

0.5/10 = 0.05

To convert it to N we have :

0.05×2 = 0.1

Using dilution formula :

N₁V₁ = N₂V₂

Where V is the volume and N the normality.

Doing the substitution:

0.5 × 100 = 0.1 × V₂

V₂ = ( 0.5 × 100) / 0.1

V₂ = 500 cm³

Given that the initial volume that was there is 100 cm³ the volume required is :

500 - 100 = 400 cm³

Answer 2

Explanation:

Given N as the normality a decinormal concentration would be:

N/2

IN This case :

0.5/10=0.05

to convert it as V we have

0.05×2=0.1

By using the formula

N1V1=N2V2

0.5×100=0.1×V2

V2=0.5×100/0.1

V2=500cm3. --–--------(Initial volume)

volume is 100 we get Initial volume -volume to get original volume

500cm3-100cm3 =400cm3