The volume of water which should be added to 300 ml of 0.5 molar naoh solution so as to get a solution of 0.2 molar is
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the volume of water never can be 300ml
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Answer:
450 ml
Explanation:
Applying the molarity equation
M1 V1 = M2 V2
(Dilute) (conc)
0.2 x V1 = 0.5 x 300
v1= 0.5 x 300 / 0.2 = 750 ml
Volume of water to be added = 750- 300 = 450ml
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