Question

The volume strength of 3% solution (w/v) of h2o2 is

Answer 1

Answer: Volume strength of $H_2O_2$ is 9.856.

Explanation: Volume strength of $H_2O_2$ is defined as the amount of $O_2$ released.

Strength of any solution can be calculated as:

Strength = Normality × Equivalent weight

Normality is calculated as:

$Normality=\frac{\text{Given mass of solute (in grams)}}{\text{Equivalent weight}\times \text{Volume (in L)}}$

We are given 3% (w/v) solution of $H_2O_2$ which means that 3 grams of hydrogen peroxide is present in 100 mL of solution.

Equivalent mass of $H_2O_2=\frac{34}{2}=17g/eq$

$Normality=\frac{3g}{17g/eq\times 0.1L}$

Normality = 29.92 eq/L

Now, 3 gram of $H_2O_2$ gives 22400mL of $O_2$ at STP

So, (1.76×17)g of $H_2O_2$ will give = $\frac{22400\times 1.76\times 17}{68}$

                                                 = 9856mL of $O_2$ at STP

But, (1.76×17)g of $H_2O_2$ is present in 100mL of $H_2O_2$ solution.

Therefore, 1000mL of $H_2O_2$ solution gives 9856mL of $O_2$ at STP.

1mL of $H_2O_2$ will give = $\frac{9856}{1000}mL$ of $O_2$ at STP.

                                   = 9.856mL of $O_2$ at STP.

Hence, the volume strength of 1.76N of $H_2O_2$ solution is 9.856 volume.

Answer 2

here's the answer and hope this helps you