Question

The volume (v) of a monatomic gas varies with its
temperature (t), as shown in the graph. The ratio
of work done by the gas, to the heat absorbed by
it, when it undergoes a change from state A tO
state B, is
[NEET-2018]
BT-cond
PO
n CpD7.
->T​

Answer 1

Answer:

2/3

Explanation:

∆Q=nCpdt eq2

and ∆U=nCvdt. eq2

dividing 1÷2 we get

∆Q/∆U=Cp/Cv

and we know Cp/Cv= Gamma

therefore

∆Q/∆U =gamma

and ∆Q=∆U+∆W (putting the value of ∆U as ∆Q/gamma)

we get ∆Q=∆Q/gamma+∆W

solving...

∆W/∆Q= gamma-1/gamma

gamma =5/3

ans 2/3

Answer 2

Explanation:

work done. Cp - Cv. Cv

--------------------. =. ---------------- =. 1 - --------

heat absorbed. Cp. Cp

1. 1

=. 1 - -----. =. 1 -. -------

y. 5/3

=. 2/5. ✓✓✓✓✓✓✓✓