Question

The volumes of ozone and chlorine diffusing during the same time are 35ml and 29ml respectively.If the molecular weight of chlorine is 71 .Calculate the molecular mass of ozone.​

Answer 1

Answer:-

Here

$\\ \sf\longmapsto \dfrac{r(O_3)}{r(Cl_2)}=\sqrt{\dfrac{M(Cl_2)}{M(O_3)}}$

Rate of diffusion in same time is proportional to volume diffused so.

$\boxed{\sf \dfrac{V(O_3)}{V(Cl_3)}=\sqrt{\dfrac{M(Cl_2)}{M(O_3)}}}$

$\\ \sf\longmapsto \dfrac{35}{29}=\sqrt{\dfrac{71}{M(O_3)}}$

$\\ \sf\longmapsto \dfrac{(35)^2}{(29)^2}=\dfrac{71}{M(O_3)}$

$\\ \sf\longmapsto M(O_3)=48.74$