Question

The volumes of two bodies are measured to be V_1 = (10.2+-0.02) cm^3 and V_2 = (6.4 +- 0.01)cm^3. Calculate sum and difference in volumes with error limits.

Answer 1

Sum and difference in volumes with error limits is :

• Given Volume of body1, V1 = (10.2 ± 0.02) cm3 and Volume of body2, V2 =(6.4 ± 0.01) cm3

• Sum of volumes = V1 +V2

= (10.2 ± 0.02) +(6.4 ± 0.01)

= (10.2 + 6.4) ± (0.02 + 0.01)

= (16.6 ± 0.03) cm3

• Difference of volumes = V1 - V2

= (10.2 ± 0.02) - (6.4 ± 0.01)

= (10.2 - 6.4) ± (0.02 + 0.01)

= (3.8 ± 0.03) cm3